tolong kawb soal 1 dan2

1) f(x) = sin (3x^2 + 1)
f'(x) = cos (3x^2 + 1) . 6x = 6x cos (3x^2 + 1)

2) h(x) = sin x . Tan x = u . v
u = sin x => u' = cos x
v = Tan x => v' = sec^2 x = 1/(cos^2 x)
h'(x) = u' v + v' u
= cos x . Tan x + 1/(cos^2 x) . sin x
= cos x . (sin x)/(cos x) + 1/(cos^2 x) . sin x
= sin x + sin x . 1/(cos^2 x)
= Sin x (1 + 1/(cos^2 x)
= Sin x (cos^2 x + 1)/(cos^2 x)
= Sin x (1 - sin^2 x + 1)/(cos^2 x)
= sin x (2 - sin^2 x)/(cos^2 x)
= Sin x (2/(cos^2 x) - (sin^2 x)/(cos^2 x))
= Sin x (2 sec^2 x - tan^2 x)
= Sin x (2 (1 + tan^2 x) - tan^2 x)
= Sin x (2 + 2tan^2 x - tan^2 x)
= Sin x (2 + tan^2 x)