Hitunglah ph campuran 100 ml HCl 0,02 M ditambah 100 ml NaOH 0,05 M

reaksi > HCl + NaOH > NaCl + H2O
mula mula (Mol) 0.002 0.005 - -
Reaksi 0.002 0.002 0.002 0.002
Sisa - 0.003 0.002 0.002

Karena menyisakan basa lemah dan garam kita gunakan rumus buffer

Karena Kb tdk diberi tahu saya gunakan 10^-5


[OH-] = Kb. mol basa lemah sisa
-------------------------------------
mol garam x valensi

= 10^-5 . 0.003 ÷ 0.002 . 1
= 3 . 10^-8 ÷ 2 . 10 ^-3
= 3 . 2 . 10^ -5
= 6. 10^-5

Poh = -log [OH-]
= - log 6. 10^-5
= 5- log 6

ph = 14 - (5 - log6)
= 9 + log 6