Tentuka harga Ph larutan NaOH 0,02 molar

[OH-] = Mb. X
= 0,02 M . 1
= 0.02 M
= 2 . 10^-2
POH = - log 2. 10^-2
PH = 14 - 2 + log 2

smga mmbntu ya
like aj ya klo bnr