Matematika

Pertanyaan

suku ke-9 barisan 162,54,18,6,2,.... adalah...
a.2/9
b.2/27
c.2/81
d.2/243

2 Jawaban

  • a = 162
    r = ?

    Kita cari dulu r

    U2 = 162×r^2-1
    54 = 162×r1
    54 = 162r
    r = 54 / 162
    r =1/3

    U9 = ar^9-1
    U9 = 162 × 1/3^8
    U9 = 162 × 1/6561
    U9 = 162/6561
  • Barisan geometri
    Dik. a = 162
    r = 54/162 = 1/3
    Dit. U9 =...?
    Jawab :
    U9 = ar^n-1
    U9 = 162 . 1/3^8
    U9 = 162 . 1/6,561
    U9 = 2/81 (C)

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