Turunan dari Y=√cos x / x^2

[tex]Mis : u = \sqrt{cos x} \\ v = x^{2} \\ y' = \frac{u' v - u v'}{v^{2}} \\ y' = \frac{ \frac{-sin x}{2 \sqrt{cos x} } . x^{2} - \sqrt{cos x} . 2x }{x^{4}} \\ y' = \frac{- sin x}{2 x^{2} \sqrt{cos x} } - \frac{2 \sqrt{cos x} }{x^{3}} \\ y' = - \frac{2 \sqrt{cos x} }{x^{3}} - \frac{sin x}{2 x^{2} \sqrt{cos x} } [/tex]