Sec 840°- cos 1170°+ tan 1410 °- sin(-600)°
Matematika
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Pertanyaan
Sec 840°- cos 1170°+ tan 1410 °- sin(-600)°
1 Jawaban
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1. Jawaban iylaa
Sec 840°- cos 1170°+ tan 1410 °- sin(-600)°
Sec 840°- cos 1170°+ tan 1410 °+ sin600°
1/Cos 840° - Cos 1170° + Tan 1410° + Sin 600°
Ingat : K.360°+α dimana K∈ bilangan bulat positif
-1/Cos 120°- Cos 90° + Tan 0° - Sin 240°
1/Cos 30° - Cos 90° + Tan 0°+ Sin 60°
1/ 1/2√2 - 0 + 0 + 1/2√2
2√2 + 1/2√2