Larutan NH3 0,1 M MEMPUNYAI pH=11 berapakah pH larutan NH4CI 0,1M??

NH3 0,1 M pH = 11

pH NH4Cl 0,1 M ... ?

*Cari Kb NH3
pH = 11
pOH = 14 - pH
pOH = 14 - 11
pOH = 3
- log [OH^-] = 3
[OH^-] = 10^-3

[OH^-] = √( Kb × Mb )
10^-3 = √( Kb × 0,1 )
(10^-3)^2 = (√( Kb × 0,1 ) )^2
10^-6 = Kb × 0,1
Kb = 10^-6/0,1
Kb = 10^-5

*pH NH4Cl 0,1 M

NH4Cl => NH4^{+} + Cl^-
. 0,1 M ...... 0,1 M ..... 0,1 M

Garam NH4Cl bersifat asam
[H^+] = √( Kw/Kb × M kation )
[H^+] = √( 10^-14/10^-5 × 0,1 )
[H^+] = √( 10^-9 × 0,1 )
[H^+] = √( 10^-10 )
[H^+] = 10^-5

pH = - log [H^+]
pH = - log 10^-5
pH = 5