jumlah akar akar persamaan suku banyak (x²+5x-2)(x²-3x+2)=0 adalah

(x² + 5x - 2).(x² - 3x + 2)
(x² + 5x - 2).(x - 2).(x - 1)
x1 = 2
x2 = 1
***** x3,4 = (-b ± akar (b² - 4.a.c) ) / 2.a
### a = koefisien x²
b = keofisien x
c = koef tanpa x

= (-5 ± akar (5² - 4.1.(-2)) ) / 2.1
= (-5 ± akar (25 + 8) ) / 2
= (-5 ± akar 33) / 2
***** x3 = (-5 + akar 33) / 2
***** x4 = (-5 - akar 33) / 2




Smoga Mmbntu..... :)