Larutan o,4 m NH4No2 hitung ph jika kb NH3 =1.10 pangkat -5...?

OH^- = akar Cb x Kb
= akar4.10^-1 × 1.10^-5
= akar 4.10^-6
=2.10^-3
pOH = -log OH^-
= -log 2.10^-3
= 3-log2
Ph = 14-pOH
= 14-(3-log2)
= 11 + log 2