5 per (x+2) + 5 per (x-2) = jawab ya...

[tex] \frac{5}{x+2} + \frac{5}{x-2} = \frac{5(x-2)+5(x+2)}{(x+2)(x-2)} = \frac{(5x-10)+(5x+10)}{x^2-4} = \frac{10x}{x^2-4} [/tex]