Luas alas balok = 120 cm. Jika Panjang = 12 cm Dan Luas Permukaan balok = 504 cm².Hitunglah volumenya

luas alas balok = persegi panjang
persegi panjang = p × l
120 = p×l = 12l
l = 120 / 12 = 10 cm
luas balok = 2 ( pl + lt + pt )
504 = 2 ( pl +lt +pt )
252 = 120 + 10t + 12t
252 - 120 = 22t
132 = 22 t
t = 132/22 = 6
volume balok = plt = 12 ×10 × 6 = 720 cm kubik

* Lebar balok :
Luas Alas Balok = p . l
120 cm² = 12 cm . l
l = 120 cm²/12 cm
l = 10 cm

Lebar balok = 10 cm

* Tinggi Balok :
Luas permukaan = 2pl + 2pt + 2lt

504 cm² = 2(12 cm.10cm) + 2 (12cm.t) + 2(10 cm.t)

504 cm² = 240 cm² + 24 cm.t + 20 cm.t
504 cm² - 240 cm² = 44cm.t
264 cm² = 44 cm.t
264 cm²/44cm = t
t = 6 cm

* volume balok :
= p.l.t
= 12 cm . 10 cm . 6 cm
= 720 cm³