tolongg kakak pr pake cara ya

mencari panjang CA
CA² = BC² + AB²
CA² = 8² + 6²
CA² = 64 + 36
CA² = 100
CA = 10

CA=FD

L(segitiga) = (1/2)at
L = (1/2)x8x6
L = 24

L(ABED) = 6x12
L = 72

L(BCFE) = 8x12
L = 96

L(ACFD) = 10x12
L= 120

L(total) = 2(24) + 72 + 96 + 120
L= 336

Alas = ∆ABC siku-siku di B,
AB = 6, BC = 8, AC = √(6^2 + 8^2) = √(36 + 64) = √100 = 10
Luas prisma = 2 luas alas + keliling alas . tinggi
= 2 . 1/2 . AB . BC + (AB + BC + AC) . AD
= 2 . 1/2 . 6 . 8 + (6 + 8 + 10) . 12
= 48 + 288
= 336 cm^2