Persamaan garis yg melalui titik (2,-3) Dan tegak lurus dgn garis 5x-2y+3=0

5x - 2y + 3 = 0
2y = 5x + 3, m1= 5
garis saling tegak lurus m1 × m2 = -1
m1×m2 = -1
5 × m2 = -1
m2 = -1/5
persamaan garis :
y - y1 = m ( x - x1)
y -3 = -1/5 ( x - 2 )
y - 3 = -1/5x + 2/5
y = -1/5x + 17/5
5y = - x + 17
x + 5y -17 = 0