Matematika

Pertanyaan

Buktikan 3tan^x - secx+1=0

1 Jawaban

  • 3tan²x - secx + 1 = 0
    3sin²x/cos²x - 1/cosx = -1
    3sin²x/cos²x - cosx/cos²x = -1
    (3sin²x - cosx)/cos²x = -1
    3sin²x - cosx = -(cos²x)
    3sin²x + cos²x = cosx
    2sin²x + sin²x + cos²x = cosx
    2sin²x + 1 = cosx
    1 = cosx - 2sin²x

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