tolong ya bantuannya ya, senin depan Un. pake cara. nomor 3

[(3log54 - 3log2)/(5log7 . √7log625 - 2log16)]^-2
= [(3log(54/2)) / (5log7 . 7^(1/2)log5^4 - 2log2^4) ]^-2
= [(3log27) / (5log7 . 4/(1/2) . 7log5 - 4 . 2log2)]^-2
= [(3log3^3) / (4/(1/2) . 5log7 . 7log5 - 4 . 1)]^-2
= [(3 . 3log3) / (8 - 4)]^-2
= [(3)/(4)]^-2
= (4/3)^2
= 16/9