Matematika

Pertanyaan

diketahui persamaan 2x+3y+16=0 dan 3x-y -10, maka nila x-y

1 Jawaban

  • 2x+3y= -16 (x1)
    3x-y = 10 (x3)

    2x+3y= -16
    9x-3y = 30
    ---------------- +
    11x = 14
    x= 14/11

    masukkan ke persamaam 1
    2x+3y = -16
    2(14/11) + 3y = -16
    28/11 +3y = -16
    3y = -16 - 28/11
    3y = -176/11 -. 28/11
    3y = -204/11
    y = -204/11 : 3
    y= -204/11 x 1/3
    y= -204/33
    nilai x -y
    14/11 - (-204/33)
    42/33+204/33
    =246/33
    maaf cek lagi yaa

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