diketahui suku banyak f(x) 2x^4+4x^2+x+1 tentukan nilai f(2)-2f(0)....

f(2) = 2(4)⁴ + 4(2)² + (2) + 1
= 2(256) + 4(4) + 3
= 512 + 16 + 3
= 531
f(0) = 2(0)⁴ + 4(0)² + (0) + 1
= 1
f(2) - 2f(0) = 531 - 2 = 529

f(x) = 2x^4 + 4x^2 + x + 1
f(2) = 2(2)^4 + 4(2)^2 + 2 + 1 = 32 + 16 + 2 + 1 = 51
f(0) = 2(0)^4 + 4(0)^2 + 0 + 1 = 1
f(2) - 2f(0) = 51 - 2(1) = 49