Integral dari 5x (1-x)^6 dx batas atas 1 batas bawah 0

int 5x(1 - x)^6 dx
u = 1 - x → du = -dx
= int -5xu^6 du
dari → u = 1 - x
x = 1 - u
= int -5(1 - u)u^6 du
= -5 int (u^6 - u^7) du
= -5((1/7)u^7 - (1/8)u^8)
= -5((1/7)(1 - x)^7 - (1/8)(1 - x)^8)
{0, 1}
= -5[(1/7)(1 - 1)^7 - (1/8)(1 - 1)^8 - {(1/7)(1 - 0)^7 - (1/8)(1 - 0)^8}]
= -5[0 - 0 - {(1/7) - (1/8)}]
= 5/56 satuan luas