Matematika

Pertanyaan

Cos 300 derajat kali Cos 30 derajat per Tan 315 derajat

1 Jawaban

  • (cos (300) × cos (30)) / tan (315)

    cos 300 = 1/2
    cos 30 = 1/2 (akar 3)
    tan 315 = sin (315) / cos (315)
    = -(1/2)(akar 2) / (1/2)(akar 2) = -1

    (1/2) × (1/2)(akar 3) / -1
    = - 1/4 (akar 3)

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