diketahui segitiga ABC dengan ukuran b=20,

<a = 180 - 105 - 45 = 30
b/sin b = a/sin a
20/sin 45 = a/sin 30
20/(1/√2) = a/(1/2)
a = 20 × 1/2 ÷ (1/√2)
a = 10×√2
a = 10√2
b/sin b = c/sin c
20/sin 45 = c/sin 105
20/(1/√2) = c/¼(√6+√2)
c = 20 × ¼(√6+√2) ÷ (1/√2)
c = 5(√6+√2) × √2
c = 5(√12+2)
c = 5√12 + 10
c = 5.2√3 + 10
c = 10√3 + 10
c = 10(√3+1)