Hasil dari integral x akar x-5 dx adalah

int x√(x - 5) dx
u = x - 5 → du = dx
= int x√u du
dari u = x - 5
x = u + 5
= int (u + 5)√u du
= int (u^(3/2) + 5u^(1/2)) du
= (2/5)u^(5/2) + (10/3)u^(3/2) + c
= (2/5)(x - 5)^(5/2) + (10/3)(x - 5)^(3/2) + c
= (2/5)√(x - 5)^5 + (10/3)√(x - 5)³ + c