Limx menuju 0 1 - cos 2x :sin 2x
Matematika
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Pertanyaan
Limx menuju 0 1 - cos 2x :sin 2x
1 Jawaban
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1. Jawaban DB45
Limit
lim(x->0) (1- cos 2x) /. sin 2x
lim(x->0) (1 - (1 - 2 sin² x) ./(2 sin x cos x)
lim(x->0) 2 sin x. sinx / 2 sinx . cos x
lim(x->0 sin x./ cos x
x = 0 --> lim = sin 0 / cos 0 = 0/1 = 0